Isolated footing concrete
Concrete Volume
0
m³
Volume of one footing
V₁ = L × W × D
= 0 × 0 × 0
= 0 m³
Total concrete
V = V₁ × No. of footings
= 0 × 0
= 0 m³
Dry volume of concrete
Dry volume = Wet volume × 1.54
= 0 × 1.54
= 0 m³
Dry ingredients bulk up; they lose ~54% volume once water is added and the mix is compacted.
Cement (M20 = 1 : 1.5 : 3, sum of ratio 5.5)
Cement volume = Dry volume × 1 / 5.5 ; bags = volume / 0.0347
= 0 × 1/5.5 = 0 m³ ÷ 0.0347
= 0 bags (0 kg)
One 50 kg bag of cement occupies 0.0347 m³ (density 1440 kg/m³).
Sand (fine aggregate)
Sand = Dry volume × 1.5 / 5.5
= 0 × 1.5/5.5
= 0 m³
Coarse aggregate (20 mm)
Aggregate = Dry volume × 3 / 5.5
= 0 × 3/5.5
= 0 m³
Water (for W/C 0.5)
Water = Cement weight × 0.50
= 0 × 0.50
= 0 litres
Method used: Rankine's earth-pressure theory for depth of foundation, with IS 456 limit-state bearing check
An isolated footing is a rectangular pad: volume = L × W × D per footing, multiplied by the number of identical footings. The material split then follows the standard M20 dry-volume method.
Estimates for guidance only. Confirm quantities with your site engineer.
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