Flooring

Tiles, adhesive and grout

Room lengthRoom widthNo. of such roomsnosDeduct area (steps, cut-outs)Skirting length (leave 0 if none)Skirting heightTile lengthTile width

Tiles Required

nos

Floor area: 0 m²
Tile area: 0 m²
Boxes (10 tiles): 0 nos
Tile adhesive: 0 bags (40 kg)
Grout: 0 kg

Mark

Quantitynos

How we got this

1
Floor area from dimensions
A = Length × Width × No. of rooms − Deductions
= 0 × 0 × 1 − 0
= 0 m²
2
Area of one tile
a = Tile length × Tile width
= 0 × 0
= 0 m²
3
Tiles without wastage
N = (Floor area + Skirting) / a
= 0 / 0
= 0 nos
4
Add 10% wastage
Order = N × 1.10 (rounded up)
= 0 × 1.10
= 0 tiles
5
Adhesive and grout
Adhesive = Area × 4 kg/m² ; Grout = Area × 0.25 kg/m²
= 0 × 4 kg and × 0.25 kg
= 0 kg adhesive · 0 kg grout

The theory behind it

Method used: Area take-off with bedding-mortar volume — IS 1443 flooring practice

Divide the floor area by the area of one tile to get the count, then add wastage for cuts at edges, corners and skirting. Adhesive is taken per m² of floor for a 4–6 mm bed.

Assumptions used

•Wastage 10% for cutting and breakage (15% for diagonal laying).
•Adhesive ≈ 4 kg/m² → 0.1 bag of 40 kg per m².
•Grout ≈ 0.25 kg/m² for 2–3 mm joints.
•Box of 10 tiles — check the actual box count with your supplier.

Codes & references

IS 15622:2017 — Pressed ceramic tiles
IS 13630 — Methods of test for ceramic tiles

History

Estimates for guidance only. Confirm quantities with your site engineer.